Question

calculate the number of molecules present in 64 gram of Oxygen gas when equal to 16 you

Answer 1

The atomic mass of an oxygen atom is 16gm
The molecular mass of an oxygen molecule is 32gm.
Hence,64/32
=2mole
each mole contain 6.02 ×10^23 particle
so,your answer is 12.04×10^23 molecules.

Answer 2

The number of molecules present in 64 grams of Oxygen gas is  =$12,046$ × $10^{23}$ molecule

Explanation:

• Mol, the symbol mol, is the SI base unit of the amount of substance. Amount of substance is a measure of how many basic units of a particular substance are in an object or sample.
• The ratio of the number of moles of one component of a solution or other mixture to the total number of moles of all  components.

The molar mass of oxygen$= 32g$

⟹ $32g O2$ Since  contains $= 6.023$× $10^{23}$,

the number of molecules present in 64 g of oxygen $= 6.023$ ×$10^{23}$× $\frac{32}{64}$

=$12,046$ × $10^{23}$ molecule

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