Question

calculate the number of molecules present in 70g of Nitrogem​

Answer 1

Answer:

15.0575 x 10^23 molecules

Explanation:

no of molecules = given mass / atomic mass * 6.023 x 10^23 molecules

given mass = 70g

atomic mass of $N_{2}$ = 2*14 = 28g

no of molecules = 70/28*6.023 x 10^23 = 15.0575 x 10^23