calculate the number of molecules present in 71 gram of N2SO4
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Molecular mass of N2SO4 = (14X2)+32+(16x4) = 124 g
So, 124g = 6.022x10^23 molecules.
71 g = 6.022x10^23 X 71 / 124 = 3.448x10^23 molecules.
So, 124g = 6.022x10^23 molecules.
71 g = 6.022x10^23 X 71 / 124 = 3.448x10^23 molecules.
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