calculate the number of molecules present in each sample
a)360g glucose (molecular mass =180)
b) 90g water (molecular mass 18)
Answers
Answer:
(A)12.046×10^23 molecules of glucose
(B)30.115×10^23 molecules of water
Explanation:
(A) Given mass = 360g
Molecular mass = 180g
No. of moles = Given mass / Molecular mass
No. of moles = 360g / 180g
= 2 moles
No. of molecules= 2 × Avogadro no.
= 2 × 6.023 × 10^23
= 12.046 × 10^23
therefore 360g glucose contains 12.046 × 10^23 molecules.
(B)Given mass = 90g
Molecular mass = 18g
No. of moles = Given mass / Molecular mass
No. of moles = 90g / 18g
= 5 moles
No. of molecules= 5 × Avogadro no.
= 6 × 6.023 × 10^23
= 30.115 × 10^23
Therefore 90g of water contains 30.115 × 10^23 molecules.
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Answer:
) = / .
=360/180
= 2
= 2
= 2 6.022 10 ²³
) = 90/18
= 5
= 2 .
= 2 6.022 10 ²³