Question

calculate the number of moles and molecules of acetic acid present in 22g of it

Answer 1

chemical formula of acetic acid is $CH_3COOH$ or $C_2H_4O_2$

so, molecular mass of acetic acid = 2 × atomic mass of C + 4 × atomic mass of H + 2 × atomic mass of O

= 2 × 12 + 4 × 1 + 2 × 16

= 24 + 4 + 32

= 60g/mol

given mass of acetic acid = 22g

so, no of moles of acetic acid = given mass/molecular mass

= 22/60 ≈ 0.367

so, number of moles of acetic acid is 0.367mol

number of molecules in 0.367 mol of acetic acid = 6.022 × 10²³ × 0.367

= 2.21 × 10²³

hence, number of molecules of acetic acid is 2.21 × 10²³

Answer 2

Answer: The number of moles and molecules of acetic acid present in given  amount is 0.367 mole and $2.21\times 10^{23}$ number of molecules respectively.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of acetic acid = 22 g

Molar mass of acetic acid = 60 g/mol

Putting values in above equation, we get:

$\text{Moles of acetic acid}=\frac{22g}{60g/mol}=0.367mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules.

So, 0.367 moles of acetic acid will contain = $0.367\times 6.022\times 10^{23}=2.21\times 10^{23}$ number of molecules.

Hence, the number of moles and molecules of acetic acid present in given  amount is 0.367 mole and $2.21\times 10^{23}$ number of molecules respectively.