calculate the number of moles and molecules present in 0.032 mg of methane (C=12,H=1)
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Explanation:
Therefore, 0.032 mg =3.2x10-5 g methane _ 3.2x10-5 - mole = 2 x 10 mole methane 16 Now, 1 mole of methane = 6.022 x 1023 molecules of methane Hence 2 x 10 mole of methane = 12.044 x 1017 molecules of methane.
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Answer:
Therefore, 0.032 mg =3.2x10-5 g methane _ 3.2x10-5 - mole = 2 x 10 mole methane 16 Now, 1 mole of methane = 6.022 x 1023 molecules of methane Hence 2 x 10 mole of methane = 12.044 x 1017 molecules of methane.
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