calculate the number of moles and molecules present in 12.5 g calcium carbonate .calculate the number
Answers
Answered by
4
HEY!!!
CACO3 = 100gm
So in 12.5gm
= Caco3 = 100/12.5
Caco3 = 6.022 ×10^23 × 8 mole.
Help u.
CACO3 = 100gm
So in 12.5gm
= Caco3 = 100/12.5
Caco3 = 6.022 ×10^23 × 8 mole.
Help u.
Anonymous:
yep! to find no of molecules =) multiply 6.023*10^23 to 8 :)
hmm
thanks
Similar questions