Question

calculate the number of moles and molecules present in 8.8g of carbon dioxide, also calculate the number of oxygen atoms present in this.

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Answer 1

Explanation:

The number of oxygen atoms present in 8.8 grams of carbon dioxide is 2.4088× atoms. Explanation: We know that the molecular formula of carbon dioxide is . ... therefore, the number of oxygen atoms present in 8.8 grams of carbon dioxide = 2× 1.2044 × = 2.4088× atoms

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Answer 2

Explanation:

No. of moles= given mass/molar mass

                    =8.8/44

                    =0.2 moles

No. of molecules= given mass/molar mass * avogadro number

                           = 8.8/44*6.022*10^23

                           = 1.2044*10^23 molecules

No. of oxygen atoms= 1.2044*10^23*2

                                  =2.4088*10^23 atomes