calculate the number of moles and the number of molecules present 1.4g of ethylene c2h4 gas
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no of moles=given mass÷molar mass
here given mass is 1.4g
and molar mass is c2h4=24+4=28gpermol
so no of moles =1.4÷28= 0.05mol
hope it is clear to u
no of moles=given mass÷molar mass
here given mass is 1.4g
and molar mass is c2h4=24+4=28gpermol
so no of moles =1.4÷28= 0.05mol
hope it is clear to u
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