Calculate the number of moles for the following:
a) 4.6g Sodium
b) 120g Carbon
c) 12.044x1023 molecules of Chlorine
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Answer:
) 4.6g Na
1 mole Na contains 23 g Na
23 g Na =1 mole of Na
1 g Na= 1/23 moles of Na
4.6 g Na= 1/23×4.6= 4.6/23=0.2 moles
Therefore 0.2 moles are present in 4.6 g of Na
b) 120g
No. of g-atoms of Carbon = \sf \frac{at.\ mass\ of\ carbon}{mass\ of\ carbon} = \frac{120}{12} = 10
mass of carbon
at. mass of carbon
=
12
120
=10
∵ 1 g-atom of carbon has no. of atoms =6.023 × 10²³
∴ 10 g-atoms of carbon has no. of atoms =10 × 6.023 × 10²³ or 10N
Explanation:
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