Calculate the number of moles in 12.044×10^23 number of helium atoms
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Answered by
281
One mole of any element contains 6.022 X 1023 atoms of the element. Thus 1 mole of He atom consists of 6.022 X 1023 atoms of He. Thus
6.022 X 1023 atoms of He = 1 mole of He atom
1 atom of He = 1 / ( 6.022 X 1023) moles of He
So 12.044 X 1023 atoms of He = ( 1 X 12.044 X 1023) / ( 6.022 X 1023) moles of He
= 2 moles of He atom
Thus there are 2 moles of He atom in 12.044 X 1023 atoms of He.
hope this helps you
6.022 X 1023 atoms of He = 1 mole of He atom
1 atom of He = 1 / ( 6.022 X 1023) moles of He
So 12.044 X 1023 atoms of He = ( 1 X 12.044 X 1023) / ( 6.022 X 1023) moles of He
= 2 moles of He atom
Thus there are 2 moles of He atom in 12.044 X 1023 atoms of He.
hope this helps you
Answered by
186
no of moles = no of atom/ Avagadro number
12.044×10^23/6.022×10^23
=2moles
12.044×10^23/6.022×10^23
=2moles
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