Question

Calculate the number of moles in 12.044*10^25 atoms of phosphorus

Answer 1

m=12.023×10^23÷6.023×10^23
=2
mole =weight/atomic weight
2×30=w
w=60gm

Answer 2

Heya user !!!

Here's the answer you are looking for

1 mole of a substance contains 6.022 × 10²³ particles.

So, there are 6.022 × 10²³ atoms in 1mole of an element

$6.022 \times {10}^{25} \: atoms \: re \: present \: in \: \frac{12.044 \times {10}^{25} }{6.022 \times {10}^{23} }$
= 2 × 10²

= 200 moles.

Therefore, 200 moles of phosphorus contains 12.044× 10^25 atoms.


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