calculate the number of moles in 25g CaCO3 and the number of oxygen atoms
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1)moles of CaCO3 = given weight ÷ molar mass
= 25÷ 100
= 0.4 moles
2)moles O in 0.4 moles=1.2
atoms of O = 1.2×6.022×10^23
= 25÷ 100
= 0.4 moles
2)moles O in 0.4 moles=1.2
atoms of O = 1.2×6.022×10^23
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