Question

Calculate the number of moles in 25g of calcium carbonate and number of oxygen atoms

Answer 1

Answer:

Calcium Carbonate = CaCO₃

Molecular mass of CaCO₃ = 40 + 12 + 3(16) = 40 + 12 + 48 = 100 g

Number of moles = (Mass of given compound)/(Molecular mass of given compound)

No.of moles = (25/100) = 0.25 moles of CaCO₃

No. of atoms in 25 g of CaCO₃ = 0.25 * 6.023 * 10²³

= 1.50575*10²³ atoms

No. of atoms of oxygen in CaCO₃ = (No. of oxygen atoms)*Total no. of atoms of the given compound

No. of atoms of oxygen in CaCO₃ = (3)*1.50575*10²³

= 4.51725*10²³

No. of atoms of oxygen in CaCO₃ = 4.51725*10²³

HOPE IT HELPS YOU

PLEASE MARK ME AS THE BRAINLIEST

Answer 2

Answer:0.25 moles

4.515×10^23 oxygen atoms

Explanation:

See the explanation

U will get it

Hope it will help

Pls mark brainliest.