Question

calculate the number of moles in 3.011 into 10 to the power 23 molecules of Nitrogen

Answer 1

One mole of Nitrogen contains 6.022 × 10²³ atoms

so, 3.011 × 10²³ atoms of nitrogen will have:

$\frac{3.011\times 10^2^3}{6.022\times 10^2^3}$ = 0.5 moles

one mole of nitrogen weighs 14g, so, 0.5 moles of nitrogen will weigh:

14 × 0.5 = 7g

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Answer 2

Answer:

The number of moles present in 3.011 × $10^{23}$ molecules of Nitrogen is 0.5 moles.

Explanation:

The mole is a unit of measurement or the starting point for determining the concentration of a chemical in a sample. Avogadro's constant, or 1 mole, is a quantity that is equal to 6.022 x $10^{23}$ particles.

Simply divide the provided weight of the substance by its molar mass to determine the number of moles of any compound that is present in the sample.

The formula for number of moles:

n = $\frac{m}{M}$

here, m = given mass of the element

M =  molar mass of the element.

1 mole of anything = 6.022x $10^{23}$ of anything

We must divide the specified number of particles by Avogadro's constant in order to determine the number of moles in this situation.

Therefore, n = $\frac{3.011 * 10^{23} }{6.022 * 10^{23} }$

(We are given with the number of atoms of Nitrogen which is 3.011 × $10^{23}$)

n = $\frac{3.011}{6.022}$

n = 0.5 moles

The number of moles present in 3.011 × $10^{23}$ molecules of Nitrogen is 0.5 moles.

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