calculate the number of moles in 44.8g of sulphur dioxide
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Answer:
2 mol
Explanation:
at ntp 1 mol of any gas = 22.4 L
1L= 1/22.4 mol
44.8= 1/22.4*44.8 mol
= 2 mol
Answered by
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no. of moles = given mass ÷ molar mass
here mass of sulphur dioxide is 44.8 g
molar mass of sulphur dioxide is 64.066 g / mol
while using the formula we get ,
no.of moles = given mass ÷ molar mass
= 44.8 ÷ 64.066
=0.69
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