Question

Calculate the number of moles in 90 ml of H2O at 1 ATM and 300 Kelvin

Answer 1

Answer:-

Given :

Volume of water (V) = 90 ml = 0.09 L

Pressure (P) = 1 atm.

Temperature (T) = 300 K

R (Gas Constant) = 0.082 L*atm/mol*K

By Ideal Gas Equation,

→ PV = nRT ( Here , n = number of moles)

→ (1)(0.09) = n(0.082)(300)

→ (0.09)/(0.082)(300) = n

→ n = 0.0036 mol.