calculate the number of moles in a) 1.11 gram of calcium chloride
b) 1.5 into 10^30 molecules of ammonia
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Answers
Answer: a. 0.01 moles
b. 2.49*10^6 moles
Explanation: For this we have to know relation :
1 mole = molecular weight = 6.023* 10^23 no. of atoms or molecules = 22.4 lit.
A. Solution : (Since, question has given relation between moles and molecular weight so my target is to relate the molecular weight and mole)
Molecular weight of CaCl2 = Ca + 2Cl = (20 + 20 ) + 2 * 35.5 = 40+ 71 = 111g
Then, we know
111 g of CaCl2 is = 1 mole of CaCl2
1 g of CaCl2 is = 1 / 111 mole of CaCl2
Therefore, 1.11 g of CaCl2 = (1*1.11 ) / 111 mole of CaCl2 = 0.01 mole of CaCl2.
B. Solution : ( Since question has given relation b/w mole and no. of molecules so my target is to relate the mole and no. of molecules)
We know,
6.023 * 10^23 no. of molecules of NH3 = 1 mole of NH3
1 no. of molecules of NH3 = 1 / 6.023* 10^23 mole of NH3
Therefore, 1.5* 10^30 no. of molecules of NH3 = 1.5*10^30 / 6.023 * 10^23
= 2.49 * 10^6 no. of moles.