calculate the number of moles in each of the following 10.0g of caco3 and 1×1023 molecules of co2
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Answer:
0.1 moles of CaCo3 and 0.166 moles of CO2,please mark this the brainliest!
Explanation:
1.)
since 1 mole of CaCO3 has the molar mass of 100 g
10g are equivalent to 10/100=0.1 moles of CaCO3
2.)
1 mole of CO2 will contain 6.022 *10²³ molecules
hence (im assuming you have written 1*10²³) molecules will be equal to
10²³/(6.022 *10²³)=0.166 moles
I hope this answer helps you!
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