calculate the number of moles in each of the following : (i) 10.0 g of CaCO3 (ii) 10(23) molecules of CO2. (Atomic mass of Ca =40 u)
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(i)Since molecular mass of CaCo3 is 100,therefore number of moles in given thing is :10/100=.1 mole
(ii)i suppose you meant 10^23
One mole contains 6.023*10^23 molecules,so no. of moles in 10^23 molecules would be :10^23/6.023*10^23=1/6.023 moles=.17 moles
(ii)i suppose you meant 10^23
One mole contains 6.023*10^23 molecules,so no. of moles in 10^23 molecules would be :10^23/6.023*10^23=1/6.023 moles=.17 moles
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Answer:
hiiiii
ur ans. of ur question (i) is-- Molar mass of CaCO3= 100g/mol
No. of moles in 10g of CaCO3 =10/100
=0.1 mol
ur answer of ques. (ii) is -- is in the attachment
Please dear mark as BRAINLIEST
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