Question

calculate the number of moles, molecules, and total number of atoms present in 1.1 * 10–3 kg of CO2​

Answer 1

Answer:

ok I calculate but give me time

Answer 2

Explanation:

1 mole of co2 contain 44g mass

therefore , 1.1g of co2 contain 1.1/44 moles

= 0.025

Hence no. of molecule =

$0.025 \times 6.23 \times {10}^{ 23}$

hence no. of atom =

$3 \times 0.025 \times 6.23 \times {10}^{23}$