Question

calculate the number of moles of 100 ml c2o42-required for complete reduction of 0.2 M 250 ml of cro2 2- iron in acidic medium​

Answer 1

The reaction is as follows:

5HC

2

O

4

−

+2MnO

4

−

→2Mn

2+

+10CO

2

The number of moles of MnO

4

−

=0.1×0.02=0.002 mol

This is equal to 0.005 mol of HC

2

O

4

−

ion. This corresponds to x g.

The number of moles of Ca(OH)

2

is 0.1×0.05=0.005 mol

They corresponds to 0.01 mol of hydrogen ions and 0.01 mol of HC

2

O

4

−

.

This is equal to y g.