Question

calculate the number of moles of Al in 2.16 moles of Al2O3​

Answer 1

Let n = number of moles .

Thus it is given that

n(Al2O3) = 2.16 mol.

n(Al) = ?

Now in 1 mole there are 2 moles of Al in Al2O3

Thus by unitary method;

n(Al) = 2 × n(Al2O3)

= 2 × 2.16

= 4.32 moles.

Therefore n(Al) = 4.32

#answerwithquality

#BAL

Answer 2

Given,

2.16 moles of Al$_2$O$_3$

To find,

Number of moles of Al

Solution,

This question can very easily be solved using stoichiometry.

In the compound, Al$_2$O$_3$

there are 2 moles of Al in 1 mole of Al$_2$O$_3$

we can apply the unitary method here  

1 mol Al$_2$O$_3$ -------> 2 mol Al

∴ 2.16 mol Al$_2$O$_3$ ------> 2.16 × 2 mol Al = 4.32 mol Al

∴ There are 4.32 mol Al, in 2.16 mol Al$_2$O$_3$.