Question

Calculate the number of moles of butane, CH, in 151 g of butane (At. masses
C=12 amu and H=1 amu). (Ans:2.63 moles)​

Answer 1

Answer:

Moles = given weight / molecular weight

Butane = C4 H10

so molecular weight = (4×12) + ( 10×1)

= 58amu

Using the above formula

Moles = 151/ 58. = 2.60 ( approx)

Answer 2

Answer:

No. of moles = 2.6 approx.

Explanation:

Molar mass = 4*12 + 1*10 = 48+10 = 58

No: of moles = Given mass/ Molar mass.

                    = 151/58.

                    = 2.6034.

                    = 2.6 approx.