calculate the number of moles of ca ,c ,o arom and their mass in 200g caco3
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Hence molecular mass of CaCO3= 40+12+{3×(16)}=100u~~ 100g. Here (given mass )=200g. ... Of moles(n) = given mass ÷( molecular mass). n=200÷100= 2 mols.
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Answer:
The answer is 200g of carbofleuromonoxides plus basic monoxides
Explanation:
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