Question

Calculate the number of moles of ethane required to produce 44g of co2after combustion
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Answer 1

Answer:

0.5

Explanation:

reaction is

C2H6 + 5/2O2 >>>> 2CO2 + H20

for 1 mole of ethane,

WEIGHT OF 2CO2 = 2 (12 + 16*2 ) = 2*44 = 88 gm

SO, 88 gm co2 = 1 mole of ethane

44gm of co2 = 1/2 mole of ethane

Answer 2

Answer:

1/2 mole of ethane is required to produce 44 grams of CO2

Explanation:

C2H6+5O2》》2CO2+3H2O