Calculate the number of moles of h2so4 required to neutralize 5 mole of naoh
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11
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Reaction for the neutralization of the H₂SO₄ and NaOH is →
H₂SO₄ + 2NaOH ------------→ Na₂SO₄ + 2H₂O
From the Reaction,
∵ 2 moles of NaOH is neutralized by the 1 moles of H₂SO₄.
∴ 1 moles of NaOH is neutralized by the 1/2 moles of H₂SO₄.
∴ 5 moles of NaOH is neutralized by the 2.5 moles of H₂SO₄.
Hence, the number of moles of the sulphuric acid required to neutralizes the 5 moles of Sodium Hydroxide.
Hope it helps.
Reaction for the neutralization of the H₂SO₄ and NaOH is →
H₂SO₄ + 2NaOH ------------→ Na₂SO₄ + 2H₂O
From the Reaction,
∵ 2 moles of NaOH is neutralized by the 1 moles of H₂SO₄.
∴ 1 moles of NaOH is neutralized by the 1/2 moles of H₂SO₄.
∴ 5 moles of NaOH is neutralized by the 2.5 moles of H₂SO₄.
Hence, the number of moles of the sulphuric acid required to neutralizes the 5 moles of Sodium Hydroxide.
Hope it helps.
Answered by
2
From the Reaction,
∵ 2 moles of NaOH is neutralized by the 1 moles of H₂SO₄.
∴ 1 moles of NaOH is neutralized by the 1/2 moles of H₂SO₄.
∴ 5 moles of NaOH is neutralized by the 2.5 moles of H₂SO₄.
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