Question

Calculate the number of moles of HCl required to neutrilize 0.5 mol of Al(OH)3 solution?

Answer 1

Answer:

      1.5 mol of HCl

Explanation:

3HCl + Al(OH)₃ ⇒ AlCl₃ + 3H₂O

1 mol of Al(OH)₃ ≡ 3 mol of HCl

0.5 mol of Al(OH)₃ ≡ 0.5 × 3 mol of HCl

                               ≡ 1.5 mol of HCl