Calculate the number of moles of KClO3 that will be required to give 6 moles of oxygen.
Answers
Answered by
74
2KClO₂ ----(On heating with MnO2 [Catalyst])----> 2KCl + 3O₂
From the above reaction. its clear that
3 moles of O₂ is given out, when 2 moles of KClO₃ decomposes.
6 moles of O₂ is given out, when (x) moles of KClO₃ decomposes.
So,
x = 6 × 2 / 3
= 4 moles.
Therefore, 4 moles of KClO₃ will be required to give 6 moles of Oxygen.
From the above reaction. its clear that
3 moles of O₂ is given out, when 2 moles of KClO₃ decomposes.
6 moles of O₂ is given out, when (x) moles of KClO₃ decomposes.
So,
x = 6 × 2 / 3
= 4 moles.
Therefore, 4 moles of KClO₃ will be required to give 6 moles of Oxygen.
Gul705:
Thanx Angella! I was stuck up with this from the past two days! Can't believe that it was this easy... Anyways thanx sooooo much! :D
Oh! My pleasure! :)
By the way, in the above mentioned reaction, it got typed as KClO₂ instead of KClO₃. I'm sorry, that was accidental!
No problem, i didn't even notice... its really sweet of u!!
:))
Answered by
32
3 moles of O₂ is given out, when 2 moles of KClO₃ decomposes.
6 moles of O₂ is given out, when (x) moles of KClO₃ decomposes.
So,
x = 6 × 2 / 3
= 4 moles
6 moles of O₂ is given out, when (x) moles of KClO₃ decomposes.
So,
x = 6 × 2 / 3
= 4 moles
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