Question

Calculate the number of moles of N, gas present in 42.5g of nitrogen ?
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Answer 1

Answer:

The number of moles of N2(g) present in 42.5 g of Nitrogen is 1.52

Explanation:

1 mole N2 = (14×2) = 28 g N2

Here,

28g N2 = 1 mole N2

1 g N2 = 1/28 mole N2

42.5 g N2 = (1/28)×42.5 mole N2

= 1.52 mole N2