Question

calculate the number of moles of nitrogen gas present in its 33.12 L?​

Answer 1

Answer:

8.903 X 10²³

Explanation:

We know that one mile of N² at S.T.P. occupies 22.4 litres and containing 6.033 X 10²³ molecules of N²

Therefore,22.4l of N² at S.T.P. contains molecule= 6.033x10²³

1 litres of N² at S.T.P. contains

Molecules = (6.022 X 10²³) / 22.4

33.12 litres of N² at S.T.P. contains

Molecules=(33.12x6.022x10²³)/22.4

= 8.903 X 10²³