Question

Calculate the number of moles of oxygen atoms and number of water molecules present in 14.3gram of washing soda.

Answer 1

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Answer 2

Gram molecular mass of Na2CO3 = 106 g
so 106g of Na2CO3 = 1mol
143g of Na2CO3 = 143 / 106 = 1.35 mol

Now, 1 mol of Na2CO3 contains = 2 x 6.022 x 1023 atoms of sodium
so 1.35 mol of Na2CO3 contains = 1.35 x 2 x 6.022 x 1023
= 16.25 x 1023 Na atoms

1 mol of Na2CO3 contains = 6.022 x 1023 atoms of carbon


1.35 mol would have = 1.35 x 6.022 x 1023
= 8.13 x 1023 carbon atoms

1 mol of Na2CO3 contains = 3 x 6.022 x 1023 atoms of oxygen

1.35 mol would have = 1.35 x 3 x 6.022 x 1023
= 24.39 x 1023 oxygen atoms