Question

Calculate the number of moles of oxygen needed for complete combustion of 58 g of Butane.​

Answer 1

Answer:

Explanation:

the balanced equation for the combustion of butane is

                   2c4h10+13o2 gives 8co2+10h2o

                      thus 13 moles of oxygen is required for the combustion of 2 moles of butane

                            thus the number of grams required=58*13/2

                                                                                          377 grams