Question

Calculate the number of moles of oxygen that occupies a volume of 224ml at 273K and 3 atm pressure

Answer 1

Explanation:

22400 ml. of oxygen at 273 K temperature and 3-atm pressure = 22400 x3/1= 67200 ml at STP.

So 224 ml of oxygen at 273 K and 3-atm = 224 x3= 672 ml at STP

The number of Oxygen molecules present in 22400 ml of gas at STP=N

(where N= Avagadro Number)

Therefore 224 ml of oxygen at 273K and 3-atm pressure will contain =Nx672/22400 x N molecules.

=3/100 x 6.022 x 10^23

=18.066 x 10^21 Molecules =1.8066x10^22 molecules...

HOPE THIS WILL HELP YOU

Answer 2

GIVEN:-

volume = 224 ml = 0.224 l

SOLUTION:-

NO. OF MOLES = GIVEN VOLUME/22.4

                          = 0.224/22.4

                          = 0.01 MOLES