Question

Calculate the number of moles of solute present in 100 g of 0.2 M KCl, density of solution = 1.2 gm/ml.

Answer 1

Answer:

Mass of 1 Litre solution = 1000 mL × 1.2 g / mL

= 1200 g

Mass of solute = 2 moles × 100 g/ mole = 200 g

Mass of solvent = 1200 -200 = 1000 g = 1 Kg

Molarity of solution = 2 M

molality = 2 moles per 1000 g the solvent = 2 m

Answer 2

Answer:

100g of solution is given

density of solution = 1.2 g/ml

then, solution in ml= 100 g/ 1.2g × ml= 1000/12 ml

Molarity = mole/ volume of solution (in L)

molarity given =0.2M

(mole/ 1000)×12×1000=0.2

so from here we can calculate mole=0.167 or 0.16666....

which is the correct ans

Explanation:

REMEMBER ANS IS ALWAYS HIDDEN IN THE QUESTION