Question

calculate the number of moles present in 9g of ethane​

Answer 1

Answer:

Molar mass of ethane is 2(molar mass of carbon) + 6(molar mass of hydrogen). Mm = 2(12) +6(1) = 30 g/gmol. Moles of ethane in 9 g is equal to 9g/(30 g/gmol)=. 3 gmol C2H6.

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Answer 2

Answer:

0.3

Step-by-step explanation:

ethane - C2H6

Its molecular mass = 12*2 + 6*1  = 30

according to mole concept;

molecular mass of a compound  ------- 1 mole of that compound    

          that is , 30 g ethane------1 mole ethane

    therefore , 9 g ethane------- (1*9)  / 30

                                            = 9/30

                                             = 0.3

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