Question

calculate the number of moles present in 9g of ethane​

Answer 1

Answer:

Molar mass of ethane is 2(molar mass of carbon) + 6(molar mass of hydrogen). Mm = 2(12) +6(1) = 30 g/gmol. Moles of ethane in 9 g is equal to 9g/(30 g/gmol)=. 3 gmol C2H6

Answer 2

Step-by-step explanation:

Molar mass of ethane is 2(molar mass of carbon) + 6(molar mass of hydrogen). Mm = 2(12) +6(1) = 30 g/gmol. Moles of ethane in 9 g is equal to 9g/(30 g/gmol)=.

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