Chemistry, asked by gangarapuprami, 1 month ago

calculate the number of moles volume particles of hydrogen gas liberated when 230g of sodium reacts with excess water

Answers

Answered by kalpanajawla433

0

2Na + 2H^2O __ 2NaOH+H^2

2mole Na reacts with 2 mole water

mole of Na =230÷23=10mole Na

mole of H^2 formed= 10÷2 =5 mole H^2O

volume of 1 mole of any gas at STP is 22.4 litre

volume of 5 mole H^2= 5×22.4= 1124 litre

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