Question

calculate the number of Na ions and SO4 ions present in 7.2 g of Na2SO4 a)6*10^23&3*10^23 b)6*10^22&3*10^22 c)3*10^23&6*10^23 d)6*10^24&3*10^24

Answer 1

Answer:

Explanation:

moles of  Na2SO4 = 7.2/142

= 0.05

0.05 mole contain = 2 * 0.05*6.022*10^23

= 6.022 * 10^22 od Na

and 0.05*6.022*10^23

= 3.011*10^22 mole of SO2

option b

Answer 2

Answer:

hi...where are you yarr...come online on atmagyan.