calculate the number of nitrogen atom present in 16g urea
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Answer:
3.2×10^23
Explanation:
N=n ×NA
= (16/60) × 6.023×10^23
0.27×6.023×10^23
1.6×10^23
no of N atoms in urea = 2
so N × 2 will be the answer
i.e. 3.2×10^23
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