Question

Calculate the number of noles of phosphorous (p4) in 248g of solid phosphorus. (Atomic mass of phosphorous=31)

Answer 1

$moles \: = \frac{given \: mass}{molecular \: mass}$

$moles \: = \frac{248}{31 \times 4 } \\ = \frac{62}{31} \\ = 2 \: moles$

answer is 2 moles. I multiplied 31 by 4 because the chemical formula P4.

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