Question

calculate
the number of oxygen
atom
in 10 g of caco3
​

Answer 1

Answer:

1.4 g / 28 g/mol × Avagrado no. => Hence, 1.6 g of oxygen molecules will contain same no.

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Answer 2

Answer:

The molecular weight of calcium carbonate is 100 g.

10 g of calcium carbonate corresponds to 0.1 mole.

One molecule of calcuim carbonate contains 5 atoms. Hence, 0.1 mole of calcium carbonate will contain

0.5 N A atoms. Here, N A is the Avogadro number.

So 0.5 x 6.022 x 10^23

= 3.011 x 10^23

Therefore, there are 3.011 x 10^23 oxygen atoms in 10 g of CaCO3