calculate the number of oxygen atom in 50 gram of caco3
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the molecular mass of CaCO3 is 100g
now 100g=mass of 1 mole CaCO3
so 50g=mass of 0.5 mole CaCO3
now the no. of CaCO3 molecule in 0.5 mole is 6.02×10^23×0.5=3.011×10^23
now no. of oxygen atom in 0.5 mole of CaCO3 =3×3.011×10^23=9.033×10^23
so the final answer is 9.033×10^23
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