Calculate the number of oxygen atoms and it weight in 50g of CaCO3.
tanushreemainak:
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Answered by
88
mol. at. of caco3=40+12+3×16=100g
100g if caco contains =3×6.022×10^23 atoms if oxygen
therefore 50g of caco3woll contain =3×6.022×10^23×50/100=9.033×10^23 atoms of oxygen
100g if caco contains =3×6.022×10^23 atoms if oxygen
therefore 50g of caco3woll contain =3×6.022×10^23×50/100=9.033×10^23 atoms of oxygen
Answered by
130
no. of moles = given wt / molecular wt = 50/100= 0.5moles
molecular wt of CaCO3 = 40+ 12 +(3x16) = 100 g
100g of CaCO3 have = 3x 6.023x10^23 no. of atoms
50g of CaCO3 will have= 3x6.023x10^23 x0.5
and wt of oxygen in 100g of CaCO3 = 48 grams
so wt of oxygen in 50 g of CaCO3= 48/2= 24grams
molecular wt of CaCO3 = 40+ 12 +(3x16) = 100 g
100g of CaCO3 have = 3x 6.023x10^23 no. of atoms
50g of CaCO3 will have= 3x6.023x10^23 x0.5
and wt of oxygen in 100g of CaCO3 = 48 grams
so wt of oxygen in 50 g of CaCO3= 48/2= 24grams
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