Question

calculate the number of oxygen atoms and its weight in 50 gram of caco3​

Answer 1

Answer:

Atoms are 3 and 48/100=.48

Explanation:

3 multiply 6.022e23

Answer 2

$\huge\red{\boxed{\bold{Solutions}}}$

• No. Of moles of CaCO3 = 50/100 = 0.5. (mol. At of CaCO3 = 100)

$\large\underline\mathrm\orange{Now}$,

• 1 molecules of CaCO3 contain 3 atom of O.

$\large\underline\mathrm\orange{Or}$

• 1 mole of CaCO3 contain 3 atom of O.

$\large\underline\mathrm\orange{Or}$

• 0.5 mole of CaCO3 contain 1.5 atom of O.

No. of atom of O = no. 1.5 × 6.022 × 10^23.

$\implies$ 9.033 × 10^23.

Wt. of atom of O = no. of moles × at. Wt. of O

$\implies$ 1.5 × 16

$\implies$ 24 g.

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