Question

Calculate the number of oxygen atoms in 02 mole of Na2CO310H2O. 156  1024​

Answer 1

Answer:

1 mole of Na2CO3.10H2O contains 13 atoms of oxygen.

0.20 mole will contain 0.20×13=2.26

Hence, no of oxygen atoms = 2.26×NA

=15.66×10^23 is the answer.