Calculate the number of oxygen atoms in 0.2 mole of Na2CO3.10H2O.
Answers
Answered by
26
Hi,
Na2CO3.10H2O, one mole of it contains 13 moles of oxygen atoms. Hence
Number of moles of oxygen atoms in one mole of Na2CO3.10H2O = 13
number of moles of oxygen atoms in 0.2 moles of Na2CO3.10H2O = 13 X 0.2 = 2.6
Now, one mole of a substance contains 6.022 X 1023 particles of the substance. Thus
number of atoms of oxygen in one mole of oxygen atom = 6.022 X 1023
number of moles of oxygen atoms in 2.6 moles of oxygen atoms = 2.6 X 6.022 X 1023 = 15.657 X 1023
= 1.566 X 1024
Thus, there are 1.566 X 1024 atoms of oxygen in 0.2 moles of Na2CO3.10H2O.
Na2CO3.10H2O, one mole of it contains 13 moles of oxygen atoms. Hence
Number of moles of oxygen atoms in one mole of Na2CO3.10H2O = 13
number of moles of oxygen atoms in 0.2 moles of Na2CO3.10H2O = 13 X 0.2 = 2.6
Now, one mole of a substance contains 6.022 X 1023 particles of the substance. Thus
number of atoms of oxygen in one mole of oxygen atom = 6.022 X 1023
number of moles of oxygen atoms in 2.6 moles of oxygen atoms = 2.6 X 6.022 X 1023 = 15.657 X 1023
= 1.566 X 1024
Thus, there are 1.566 X 1024 atoms of oxygen in 0.2 moles of Na2CO3.10H2O.
shivanisha:
Did u get it
Answered by
0
Answer:
0.2 moles of Na2CO3.10H2O contains 15.657×10²³ of oxygen atoms.
Explanation:
As one mole of hydrated sodium bicarbonate (Na2CO3.10H20) contains a total of 13 oxygen atoms.
So, 0.2 mole of Na2CO3.10H2O contains 13 × 0.2= 2.6 moles of Oxygen atom.
Since 1 mole of oxygen atom has 6.022×10²³ particles. Therefore,
2.6 mole of Oxygen atom has 2.6×6.022×10²³= 15.657 × 10²³
#SPJ3
Similar questions
English,
7 months ago
Math,
7 months ago
Physics,
1 year ago
Math,
1 year ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago