Question

calculate the number of oxygen atoms in 20 grams of CaCo3
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Answer 1

Answer:

Molecular weight of CaCO

3

is 100. So, number of moles present in 20g of CaCO

3

are 20/100=0.2. Each molecule of CaCO

3

has 5 atoms. So, total no. of atoms present are 0.2×5.Na=6.023×10

23

Answer 2

Answer:3 atoms of oxygen are present in 1 molecule of CaCO3 so in 0.2 mole of calcium carbonate the oxygen atoms will be. 3*0.2* na atoms of oxygen ;where na= 6x10^23

answer is in the attachment