Calculate the number of oxygen atoms in 50 g of CaCO3
1 point
(a) 6.033×10^23
(b) 9.033×10^23
(c) 8.033×10^23
(d) 3.033×10^23
Answers
Answered by
1
Answer:
b) 9.033×10^23
Explanation:
M.wt of CaCO
3
=100
number of moles of CaCO_3 present in 50gm =
100
50
=0.5
1 mole of CaCO
3
= 3 moles of O
2
0.5 moles of CaCO
3
has 1.5 moles of oxygen.
1mole=6.022∗10
23
particles
∴ 50g of CaCO
3
=1.5∗(6.022∗10
23
)=9.035∗10
23
oxygen atoms.
Answered by
0
Answer:
(a) 3.02 x 10^23
(b) 4.52 x 10^23
(c) 4.02 x 10^23
(d) 1.52 x 10^23
Explanation:
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