calculate the number of oxygen atoms in 50g of CaCo_3
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no. of moles = given wt / molecular wt = 50/100= 0.5moles
molecular wt of CaCO3 = 40+ 12 +(3x16) = 100 g
100g of CaCO3 have = 3x 6.023x10^23 no. of atoms
50g of CaCO3 will have= 3x6.023x10^23 x0.5
and wt of oxygen in 100g of CaCO3 = 48 grams
so wt of oxygen in 50 g of CaCO3= 48/2= 24grams...
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